How to use @StateObject to create and monitor external objects
How to use @StateObject to create and monitor external objects 관련
Updated for Xcode 15
SwiftUI's @StateObject property wrapper is a specialized form of @ObservedObject, having all the same functionality with one important addition: it should be used to create observed objects, rather than just store one that was passed in externally.
When you add a property to a view using @StateObject, SwiftUI considers that view to be the owner of the observable object. All other views where you pass that object should use @ObservedObject.
This really matters. Seriously, if you get this wrong you might find your object gets destroyed by accident, which will cause your app to crash seemingly randomly.
So, to be clear: you should create your observable object somewhere using @StateObject, and in all subsequent places where you pass that object you should use @ObservedObject.
Here's an example in code:
// An example class to work with
class Player: ObservableObject {
@Published var name = "Taylor"
@Published var age = 26
}
// A view that creates and owns the Player object.
struct ContentView: View {
@StateObject var player = Player()
var body: some View {
NavigationStack {
NavigationLink {
PlayerNameView(player: player)
} label: {
Text("Show detail view")
}
}
}
}
// A view that monitors the Player object for changes, but
// doesn't own it.
struct PlayerNameView: View {
@ObservedObject var player: Player
var body: some View {
Text("Hello, \(player.name)!")
}
}
If you're finding it hard to remember the distinction, try this: whenever you see “State” in a property wrapper, e.g. @State, @StateObject, @GestureState, it means “the current view owns this data.”
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